1. **Problem Statement:** Identify which shapes on the graph are congruent to shape 1 after performing the given sequences of transformations.
2. **Transformations to apply on shape 1:**
- 90° clockwise rotation about the origin, then reflection across the x-axis.
- 90° counterclockwise rotation about the origin, then reflection across the x-axis.
- 180° rotation about the origin, then translation right 4 units.
3. **Recall transformation rules:**
- Rotation 90° clockwise about origin: $(x,y) \to (y,-x)$
- Rotation 90° counterclockwise about origin: $(x,y) \to (-y,x)$
- Rotation 180° about origin: $(x,y) \to (-x,-y)$
- Reflection across x-axis: $(x,y) \to (x,-y)$
- Translation right 4 units: $(x,y) \to (x+4,y)$
4. **Coordinates of shape 1 center:** approximately $(12,14)$.
5. **Apply first transformation:**
- Rotate 90° clockwise: $(12,14) \to (14,-12)$
- Reflect across x-axis: $(14,-12) \to (14,12)$
6. **Apply second transformation:**
- Rotate 90° counterclockwise: $(12,14) \to (-14,12)$
- Reflect across x-axis: $(-14,12) \to (-14,-12)$
7. **Apply third transformation:**
- Rotate 180°: $(12,14) \to (-12,-14)$
- Translate right 4 units: $(-12,-14) \to (-8,-14)$
8. **Compare transformed centers to given shapes:**
- First transformation result: $(14,12)$ — no shape exactly here.
- Second transformation result: $(-14,-12)$ — close to brown diamond near $(-12,-10)$.
- Third transformation result: $(-8,-14)$ — no shape exactly here.
9. **Conclusion:** Only the second transformation places shape 1 congruently near the brown diamond at $(-12,-10)$, considering approximate coordinates.
**Final answer:** The brown diamond near $(-12,-10)$ is congruent to shape 1 after the second transformation.
Shape Congruence
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