Subjects geometry

Shape Congruence

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1. **Problem Statement:** Identify which shapes on the graph are congruent to shape 1 after performing the given sequences of transformations. 2. **Transformations to apply on shape 1:** - 90° clockwise rotation about the origin, then reflection across the x-axis. - 90° counterclockwise rotation about the origin, then reflection across the x-axis. - 180° rotation about the origin, then translation right 4 units. 3. **Recall transformation rules:** - Rotation 90° clockwise about origin: $(x,y) \to (y,-x)$ - Rotation 90° counterclockwise about origin: $(x,y) \to (-y,x)$ - Rotation 180° about origin: $(x,y) \to (-x,-y)$ - Reflection across x-axis: $(x,y) \to (x,-y)$ - Translation right 4 units: $(x,y) \to (x+4,y)$ 4. **Coordinates of shape 1 center:** approximately $(12,14)$. 5. **Apply first transformation:** - Rotate 90° clockwise: $(12,14) \to (14,-12)$ - Reflect across x-axis: $(14,-12) \to (14,12)$ 6. **Apply second transformation:** - Rotate 90° counterclockwise: $(12,14) \to (-14,12)$ - Reflect across x-axis: $(-14,12) \to (-14,-12)$ 7. **Apply third transformation:** - Rotate 180°: $(12,14) \to (-12,-14)$ - Translate right 4 units: $(-12,-14) \to (-8,-14)$ 8. **Compare transformed centers to given shapes:** - First transformation result: $(14,12)$ — no shape exactly here. - Second transformation result: $(-14,-12)$ — close to brown diamond near $(-12,-10)$. - Third transformation result: $(-8,-14)$ — no shape exactly here. 9. **Conclusion:** Only the second transformation places shape 1 congruently near the brown diamond at $(-12,-10)$, considering approximate coordinates. **Final answer:** The brown diamond near $(-12,-10)$ is congruent to shape 1 after the second transformation.