1. **Problem Statement:** We are given two shapes: - A teardrop-shaped figure with a circular top of radius 5 cm and two sides each of length 6 cm. - A shape resembling a square with four semicircles on each side, each semicircle having diameter 8 m. 2. **Teardrop Shape Analysis:** - The circular top has radius $r = 5$ cm. - The circumference of the full circle would be $2\pi r = 2\pi \times 5 = 10\pi$ cm. - Since the top is a semicircle, its perimeter contribution is half the circumference plus the diameter: $\pi r + 2r = 5\pi + 10$ cm. - The two sides each have length 6 cm, so total side length is $2 \times 6 = 12$ cm. - Total perimeter of the teardrop shape is $5\pi + 10 + 12 = 5\pi + 22$ cm. 3. **Square with Semicircles Analysis:** - Each side of the square has length equal to the diameter of the semicircle, $d = 8$ m. - The square perimeter is $4 \times 8 = 32$ m. - Each side has a semicircle with diameter 8 m, so radius $r = 4$ m. - The circumference of a full circle with radius 4 m is $2\pi r = 8\pi$ m. - Each semicircle perimeter is half the circumference: $4\pi$ m. - There are 4 semicircles, so total semicircle perimeter is $4 \times 4\pi = 16\pi$ m. - The total perimeter of the shape is the square perimeter plus the semicircle arcs: $32 + 16\pi$ m. 4. **Summary:** - Teardrop perimeter: $$5\pi + 22 \text{ cm} \approx 5 \times 3.1416 + 22 = 15.708 + 22 = 37.708 \text{ cm}$$ - Square with semicircles perimeter: $$32 + 16\pi \text{ m} \approx 32 + 16 \times 3.1416 = 32 + 50.265 = 82.265 \text{ m}$$ These calculations describe the perimeter lengths of the given shapes based on the provided dimensions.