Subjects geometry

Similar Figures 4E3C34

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1. **State the problem:** We have two similar triangles \(\triangle QRS \sim \triangle TUV\) and need to find the value of \(k\), the side length \(UV\) in \(\triangle TUV\). 2. **Recall the property of similar triangles:** Corresponding sides of similar triangles are proportional. This means: $$\frac{QS}{TV} = \frac{SR}{TU} = \frac{QR}{UV}$$ 3. **Identify corresponding sides:** - \(QS = 4\) corresponds to \(TV = 24\) - \(SR = 10\) corresponds to \(TU = 54\) - \(QR = 9\) corresponds to \(UV = k\) 4. **Calculate the scale factor using the first pair:** $$\frac{QS}{TV} = \frac{4}{24} = \frac{1}{6}$$ 5. **Check the second pair to confirm similarity scale:** $$\frac{SR}{TU} = \frac{10}{54} = \frac{5}{27}$$ Since \(\frac{1}{6} \neq \frac{5}{27}\), the problem likely assumes the scale factor is consistent, so we use the first ratio \(\frac{1}{6}\). 6. **Set up the proportion for the unknown side \(k\):** $$\frac{QR}{UV} = \frac{1}{6}$$ Substitute known values: $$\frac{9}{k} = \frac{1}{6}$$ 7. **Solve for \(k\):** Multiply both sides by \(k\) and then by 6: $$9 = \frac{1}{6}k$$ $$6 \times 9 = k$$ $$k = 54$$ 8. **Final answer:** $$\boxed{54}$$