1. **State the problem:** We have two similar rectangles ABDE and BCFA. We know the dimensions of BCFA are 15 m (height) and 7.5 m (width). We need to find the length of wall FE in rectangle ABDE. 2. **Recall the property of similar rectangles:** Similar rectangles have proportional corresponding sides. This means the ratio of corresponding sides in ABDE and BCFA is the same. 3. **Identify corresponding sides:** In BCFA, the height is 15 m and width is 7.5 m. In ABDE, the height corresponds to 25 m (given) and the width corresponds to FE (which is $x$). 4. **Set up the proportion:** $$\frac{\text{height of ABDE}}{\text{height of BCFA}} = \frac{\text{width of ABDE}}{\text{width of BCFA}}$$ Substitute known values: $$\frac{25}{15} = \frac{x}{7.5}$$ 5. **Solve for $x$:** Multiply both sides by 7.5: $$7.5 \times \frac{25}{15} = x$$ Simplify the fraction: $$7.5 \times \frac{\cancel{25}}{\cancel{15}} = 7.5 \times \frac{5}{3} = x$$ Calculate: $$x = 7.5 \times \frac{5}{3} = \frac{7.5 \times 5}{3} = \frac{37.5}{3} = 12.5$$ 6. **Conclusion:** The length of wall FE is $12.5$ meters.