1. **State the problem:** We have two similar teddy bears. The larger bear has height 36 and width 21. The smaller bear has width 7 and height $H$. We need to find $H$. 2. **Recall the property of similar figures:** Corresponding sides of similar figures are proportional. This means the ratio of heights equals the ratio of widths. 3. **Set up the proportion:** $$\frac{\text{height of large bear}}{\text{height of small bear}} = \frac{\text{width of large bear}}{\text{width of small bear}}$$ Substitute the known values: $$\frac{36}{H} = \frac{21}{7}$$ 4. **Simplify the right side:** $$\frac{21}{7} = 3$$ So the equation becomes: $$\frac{36}{H} = 3$$ 5. **Solve for $H$:** Multiply both sides by $H$: $$36 = 3H$$ Divide both sides by 3: $$\frac{36}{\cancel{3}} = \frac{3H}{\cancel{3}}$$ $$12 = H$$ 6. **Answer:** The height $H$ of the smaller teddy bear is $12$.