1. **State the problem:**
We have two similar triangles ABC and EBD with sides AB = 9 ft, AC = h, DE = 7 ft, and BE = 15 ft. We need to find the unknown side length $h$.
2. **Formula and rules:**
For similar triangles, corresponding sides are proportional. This means:
$$\frac{AB}{DE} = \frac{AC}{BE}$$
3. **Set up the proportion:**
$$\frac{9}{7} = \frac{h}{15}$$
4. **Solve for $h$:**
Cross multiply:
$$9 \times 15 = 7 \times h$$
$$135 = 7h$$
Divide both sides by 7:
$$\frac{135}{\cancel{7}} = \frac{7h}{\cancel{7}}$$
$$h = \frac{135}{7}$$
5. **Simplify the fraction:**
$$h \approx 19.29$$ ft
**Answer:** The unknown side length $h$ is approximately 19.29 ft.
Similar Triangles 7125D7
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