1. **State the problem:** We have a right triangle $\triangle KLM$ with $\angle M = 90^\circ$, sides $KM = 48$, $ML = 55$, and hypotenuse $LK = 73$. We want to find the ratio that represents $\sin \angle L$. 2. **Recall the sine definition:** In a right triangle, $\sin$ of an angle is the ratio of the length of the side opposite the angle to the hypotenuse. 3. **Identify the sides relative to $\angle L$:** - The hypotenuse is $LK = 73$. - The side opposite $\angle L$ is $KM = 48$ (since $\angle M$ is right, $KM$ is opposite $L$). 4. **Write the sine ratio:** $$\sin \angle L = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{KM}{LK} = \frac{48}{73}$$ 5. **Final answer:** $$\boxed{\sin \angle L = \frac{48}{73}}$$