1. **State the problem:** We need to find the horizontal distance between two skyscrapers given the angle of inclination from the base of skyscraper A to the top of skyscraper B is $12.5^\circ$ and the height of skyscraper B is 1477 feet. 2. **Identify the right triangle and trigonometric function:** The height of skyscraper B is the side opposite the angle, and the distance between the skyscrapers is the adjacent side. We use the tangent function: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ 3. **Write the formula for distance:** $$\tan(12.5^\circ) = \frac{1477}{\text{distance}} \implies \text{distance} = \frac{1477}{\tan(12.5^\circ)}$$ 4. **Calculate the tangent:** $$\tan(12.5^\circ) \approx 0.2217$$ 5. **Calculate the distance:** $$\text{distance} = \frac{1477}{0.2217}$$ 6. **Simplify the fraction:** $$\text{distance} = \frac{1477}{\cancel{0.2217}} \approx 6661.54$$ 7. **Final answer:** The distance between the two skyscrapers is approximately **6661.54 feet**.