1. **State the problem:** We have a 45°-45°-90° right triangle with one leg labeled $c$ and the other leg labeled $3\sqrt{2}$ cm. We need to find $c$ in simplest radical form.
2. **Recall the properties of a 45°-45°-90° triangle:** In such a triangle, the legs are congruent, and the hypotenuse is $\sqrt{2}$ times the length of each leg.
3. **Identify the sides:** Since the triangle is 45°-45°-90°, the two legs are equal, and the hypotenuse is opposite the right angle.
4. **Given:** The side labeled $3\sqrt{2}$ cm is the hypotenuse.
5. **Use the formula for the hypotenuse:**
$$\text{hypotenuse} = \text{leg} \times \sqrt{2}$$
6. **Set up the equation:**
$$3\sqrt{2} = c \times \sqrt{2}$$
7. **Divide both sides by $\sqrt{2}$ to solve for $c$:**
$$c = \frac{3\sqrt{2}}{\sqrt{2}}$$
8. **Cancel $\sqrt{2}$:**
$$c = 3\cancel{\sqrt{2}} / \cancel{\sqrt{2}} = 3$$
9. **Final answer:**
$$c = 3$$
So, the length of side $c$ is 3 centimeters.
Special Right Triangle 2A7E11
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