1. **State the problem:** Calculate the volume $V$ of a sphere with radius $R = 9.9$ m. 2. **Formula:** The volume of a sphere is given by $$V = \frac{4}{3} \pi R^3$$ where $\pi \approx 3.14$. 3. **Substitute the values:** $$V = \frac{4}{3} \times 3.14 \times (9.9)^3$$ 4. **Calculate the cube of the radius:** $$9.9^3 = 9.9 \times 9.9 \times 9.9 = 970.299$$ 5. **Multiply by $\pi$ and $\frac{4}{3}$:** $$V = \frac{4}{3} \times 3.14 \times 970.299$$ 6. **Calculate $\frac{4}{3} \times 3.14$ first:** $$\frac{4}{3} \times 3.14 = \frac{4 \times 3.14}{3} = \frac{12.56}{3} = 4.186666\ldots$$ 7. **Multiply by 970.299:** $$V = 4.186666\ldots \times 970.299 = 4060.208\ldots$$ 8. **Round to the nearest tenth:** $$V \approx 4060.2 \text{ m}^3$$ **Final answer:** $$\boxed{4060.2 \text{ m}^3}$$