1. The problem asks for the volume of a sphere with a diameter of 4 inches. 2. The formula for the volume of a sphere is $$V = \frac{4}{3} \pi r^3$$ where $r$ is the radius. 3. Since the diameter is 4 inches, the radius $r$ is half of that: $$r = \frac{4}{2} = 2$$ inches. 4. Substitute $r = 2$ into the volume formula: $$V = \frac{4}{3} \pi (2)^3$$ 5. Calculate the cube of 2: $$2^3 = 8$$ 6. So, $$V = \frac{4}{3} \pi \times 8 = \frac{4}{3} \times 8 \pi$$ 7. Multiply the constants: $$\frac{4}{3} \times 8 = \frac{4 \times 8}{3} = \frac{32}{3}$$ 8. Therefore, the volume is: $$V = \frac{32}{3} \pi$$ cubic inches. The volume of the sphere is $$\frac{32}{3} \pi$$ cubic inches.