1. **State the problem:** We need to approximate the volume of a sphere with radius $r=2$ inches. 2. **Formula for the volume of a sphere:** $$V = \frac{4}{3} \pi r^3$$ where $V$ is the volume, $\pi$ is approximately 3.14, and $r$ is the radius. 3. **Substitute the given values:** $$V = \frac{4}{3} \times 3.14 \times 2^3$$ 4. **Calculate the cube of the radius:** $$2^3 = 2 \times 2 \times 2 = 8$$ 5. **Plug in the value:** $$V = \frac{4}{3} \times 3.14 \times 8$$ 6. **Multiply $3.14$ and $8$:** $$3.14 \times 8 = 25.12$$ 7. **Calculate the volume:** $$V = \frac{4}{3} \times 25.12$$ 8. **Multiply numerator and denominator to simplify:** $$V = \frac{\cancel{4} \times 25.12}{\cancel{3}} \times \frac{1}{1} = \frac{100.48}{3}$$ 9. **Divide to get the volume:** $$V = 33.4933...$$ 10. **Round to the nearest tenth:** $$V \approx 33.5$$ **Final answer:** The volume of the sphere is approximately **33.5 in$^3$**.