1. **Problem Statement:** Calculate the area and perimeter of a square with side length $s = 52$ inches. 2. **Formulas:** - Area of a square: $\text{Area} = s^2$ - Perimeter of a square: $\text{Perimeter} = 4s$ 3. **Calculations:** - Area: $$52^2 = 2704$$ - Perimeter: $$4 \times 52 = 208$$ 4. **Type:** Since all sides are equal and all angles are right angles, the shape is a **Square**. **Final answers:** - Area: 2704 square inches - Perimeter: 208 inches - Type: Square