1. **Problem Statement:** Calculate the area and perimeter of a square with side length $s = 56$ ft. 2. **Formulas:** - Area of a square: $$\text{Area} = s^2$$ - Perimeter of a square: $$\text{Perimeter} = 4s$$ 3. **Calculations:** - Area: $$56^2 = 3136$$ - Perimeter: $$4 \times 56 = 224$$ 4. **Type:** Since all sides are equal and all angles are right angles, the shape is a **Square**. **Final answers:** - Area: 3136 ft² - Perimeter: 224 ft - Type: Square