1. **State the problem:** We have two squares, P and Q. One side of square P is 4 inches. 2. The area of square P is 4 times the area of square Q. 3. **Formula for the area of a square:** $$\text{Area} = \text{side}^2$$ 4. Calculate the area of square P: $$\text{Area}_P = 4^2 = 16 \text{ square inches}$$ 5. Since the area of square P is 4 times the area of square Q, let the area of square Q be $A_Q$: $$16 = 4 \times A_Q$$ 6. Solve for $A_Q$: $$A_Q = \frac{16}{4}$$ $$A_Q = \cancel{\frac{16}{4}} = 4 \text{ square inches}$$ 7. **Final answer:** - Area of square P = 16 square inches - Area of square Q = 4 square inches