1. **Problem Statement:** Find the surface area of a square pyramid given its net. The net consists of a square base with side length 10 m and four congruent triangular faces each with base 10 m and height 8 m. 2. **Formula for Surface Area of a Square Pyramid:** The surface area $S$ is the sum of the area of the square base and the areas of the four triangular faces: $$S = \text{Area of base} + 4 \times \text{Area of one triangle}$$ 3. **Calculate the area of the square base:** $$\text{Area of base} = 10 \times 10 = 100 \text{ m}^2$$ 4. **Calculate the area of one triangular face:** The area of a triangle is given by: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ Substitute base = 10 m and height = 8 m: $$\text{Area} = \frac{1}{2} \times 10 \times 8 = 40 \text{ m}^2$$ 5. **Calculate the total area of the four triangular faces:** $$4 \times 40 = 160 \text{ m}^2$$ 6. **Calculate the total surface area:** $$S = 100 + 160 = 260 \text{ m}^2$$ **Final answer:** The surface area of the square pyramid is **260 m²**.