1. The problem is to find the volume of the square pyramid at the START position, which has a base edge of 6 inches and height 6 inches. 2. The formula for the volume of a square pyramid is: $$V = \frac{1}{3} \times \text{Base Area} \times \text{Height}$$ where the base area for a square is: $$\text{Base Area} = \text{side}^2$$ 3. Calculate the base area: $$\text{Base Area} = 6^2 = 36$$ 4. Substitute the base area and height into the volume formula: $$V = \frac{1}{3} \times 36 \times 6$$ 5. Simplify the multiplication: $$V = \frac{1}{3} \times 216$$ 6. Simplify the fraction: $$V = \cancel{\frac{1}{3}} \times \cancel{216} = 72$$ 7. Therefore, the volume of the square pyramid at the START is: $$\boxed{72}$$ Note: The user asked to complete all pyramids but per instructions, only the first problem is solved here.