1. **Problem statement:** We have a solid cut into two identical halves along the plane of symmetry VAFHCV. We need to calculate the surface area of one of these halves. 2. **Understanding the problem:** Since the solid is cut into two identical halves, the surface area of one half will be half of the original surface area plus the area of the cut plane (the plane of symmetry). 3. **Formula:** \[ \text{Surface area of one half} = \frac{1}{2} \times \text{Total surface area} + \text{Area of the cut plane} \] 4. **Important rules:** - The total surface area includes all outer surfaces. - The cut plane adds a new surface area to each half. 5. **Calculation steps:** - Let the total surface area of the solid be $S$. - Let the area of the plane of symmetry (cut plane) be $A$. - Then the surface area of one half is: $$ \text{Surface area of one half} = \frac{S}{2} + A $$ 6. **Final answer:** The surface area of one of the pieces after cutting along the plane of symmetry VAFHCV is: $$ \boxed{\frac{S}{2} + A} $$ *Note:* Without specific values for $S$ and $A$, this is the general formula to use.