1. **State the problem:** Find the surface area of a rectangular prism with dimensions 8 cm (length), 3 cm (height), and 2 cm (width) using its net. 2. **Formula for surface area of a rectangular prism:** $$\text{Surface Area} = 2(lw + lh + wh)$$ where $l$ = length, $w$ = width, and $h$ = height. 3. **Calculate the area of the front and back rectangles:** These are the rectangles with dimensions height $h = 3$ cm and width $w = 2$ cm. $$\text{Area}_{front/back} = h \times w = 3 \times 2 = 6 \text{ cm}^2$$ Since there are two such rectangles (front and back): $$2 \times 6 = 12 \text{ cm}^2$$ 4. **Calculate the area of the side rectangles:** These rectangles have dimensions length $l = 8$ cm and height $h = 3$ cm. $$\text{Area}_{sides} = l \times h = 8 \times 3 = 24 \text{ cm}^2$$ Two side rectangles: $$2 \times 24 = 48 \text{ cm}^2$$ 5. **Calculate the area of the top and bottom rectangles:** These rectangles have dimensions length $l = 8$ cm and width $w = 2$ cm. $$\text{Area}_{top/bottom} = l \times w = 8 \times 2 = 16 \text{ cm}^2$$ Two top/bottom rectangles: $$2 \times 16 = 32 \text{ cm}^2$$ 6. **Calculate total surface area:** $$\text{Surface Area} = 12 + 48 + 32 = 92 \text{ cm}^2$$ **Final answer:** - Front and back rectangles area: $12$ cm² - Side rectangles area: $48$ cm² - Top and bottom rectangles area: $32$ cm² - Surface area of the prism: $92$ cm²