1. **State the problem:** We need to find the area of the top of a table composed of rectangles and triangles with given dimensions in inches. 2. **Identify the shapes and dimensions:** The figure includes: - Two right triangles on the top-left and bottom-left corners, each with legs of 30 inches. - Rectangles with dimensions 30 in. by 30 in. - The total length at the bottom is 100 inches. 3. **Formula for area:** - Area of a rectangle = $\text{length} \times \text{width}$ - Area of a right triangle = $\frac{1}{2} \times \text{base} \times \text{height}$ 4. **Calculate the area of the two triangles:** $$\text{Area}_{\triangle} = 2 \times \frac{1}{2} \times 30 \times 30 = 2 \times 450 = 900$$ 5. **Calculate the area of the rectangles:** - The total length is 100 inches. - The two triangles occupy 30 inches each on the left side vertically, so the remaining length for rectangles is $100 - 30 = 70$ inches. - The height of the rectangles is 30 inches. $$\text{Area}_{\text{rectangles}} = 70 \times 30 = 2100$$ 6. **Add the areas together:** $$\text{Total area} = \text{Area}_{\triangle} + \text{Area}_{\text{rectangles}} = 900 + 2100 = 3000$$ 7. **Answer:** The area of the top of the table is **3000 square inches**.