1. **State the problem:** We need to find the value of $\tan E$ in the right triangle $EDC$ where $ED=24$, $DC=32$, and hypotenuse $EC=40$. The right angle is at $D$.
2. **Recall the definition of tangent:** In a right triangle, $\tan$ of an angle is the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.
3. **Identify sides relative to angle $E$:**
- Opposite side to angle $E$ is $DC=32$.
- Adjacent side to angle $E$ is $ED=24$.
4. **Write the formula:**
$$\tan E = \frac{\text{opposite}}{\text{adjacent}} = \frac{DC}{ED} = \frac{32}{24}$$
5. **Simplify the fraction:**
$$\tan E = \frac{32}{24} = \frac{\cancel{32}}{\cancel{24}} = \frac{4}{3}$$
6. **Calculate the decimal value:**
$$\tan E = \frac{4}{3} \approx 1.3333$$
7. **Round to the nearest hundredth:**
$$\tan E \approx 1.33$$
**Final answer:** $\boxed{1.33}$
Tan E 1E9A7A
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