1. **State the problem:** We need to find the total volume of a wedding tent composed of a right rectangular prism and a rectangular pyramid on top. 2. **Identify dimensions:** - Prism dimensions: length $l=40$ ft, width $w=29$ ft, height $h=7$ ft - Pyramid height $H=4$ ft 3. **Formulas:** - Volume of prism: $$V_{prism} = l \times w \times h$$ - Volume of rectangular pyramid: $$V_{pyramid} = \frac{1}{3} \times l \times w \times H$$ 4. **Calculate prism volume:** $$V_{prism} = 40 \times 29 \times 7 = 8120$$ 5. **Calculate pyramid volume:** $$V_{pyramid} = \frac{1}{3} \times 40 \times 29 \times 4$$ $$= \frac{1}{3} \times 4640$$ $$= \frac{\cancel{4640}}{3}$$ (4640 is not divisible by 3, so keep fraction) $$= 1546.666\ldots$$ 6. **Calculate total volume:** $$V_{total} = V_{prism} + V_{pyramid} = 8120 + 1546.666\ldots = 9666.666\ldots$$ 7. **Round to nearest tenth:** $$V_{total} \approx 9666.7$$ ft$^3$ **Final answer:** The total volume of the tent is approximately $9666.7$ cubic feet.