1. **Problem statement:** Find the volume of the tetrahedron bounded by the coordinate planes $x=0$, $y=0$, $z=0$ and the plane $$\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1.$$\n\n2. **Formula and explanation:** The volume $V$ of a tetrahedron bounded by the coordinate planes and a plane intercepting the axes at $(a,0,0)$, $(0,b,0)$, and $(0,0,c)$ is given by \n$$V = \frac{1}{6} \times \text{(product of intercepts)} = \frac{1}{6}abc.$$\nThis comes from the fact that the tetrahedron is a pyramid with base area $\frac{1}{2}ab$ (triangle in $xy$-plane) and height $c$, and volume of a pyramid is $\frac{1}{3} \times \text{base area} \times \text{height}$.\n\n3. **Intermediate work:**\n- The plane intercepts the axes at $x=a$, $y=b$, and $z=c$.\n- The tetrahedron is formed by these intercepts and the coordinate planes.\n- Volume formula: $$V = \frac{1}{6}abc.$$\n\n4. **Final answer:**\n$$\boxed{V = \frac{abc}{6}}.$$