1. **Problem statement:** Determine if 18-cm by 24-cm tiles can cover a floor measuring 6.48 m by 15.12 m without cutting tiles. 2. **Convert floor dimensions to centimeters:** - $6.48 \text{ m} = 6.48 \times 100 = 648 \text{ cm}$ - $15.12 \text{ m} = 15.12 \times 100 = 1512 \text{ cm}$ 3. **Recall tile dimensions:** Each tile is $18 \text{ cm} \times 24 \text{ cm}$. 4. **Check if floor dimensions are multiples of tile dimensions:** - $\frac{648}{18} = 36$ (an integer) - $\frac{1512}{24} = 63$ (an integer) 5. **Interpretation:** Since both floor dimensions are exact multiples of the tile dimensions, the tiles can cover the floor completely without cutting. 6. **Final answer:** Yes, the tiles can be used to cover the floor of $6.48 \text{ m} \times 15.12 \text{ m}$ without cutting.