1. The problem gives a rectangular scale drawing of a trampoline with width $w = 5$ inches and length $l = 8$ inches. 2. The scale is $1$ inch : $2$ feet, meaning each inch on the drawing represents $2$ feet in real life. 3. To find the actual width and length of the trampoline, multiply the drawing dimensions by the scale factor. 4. Actual width $= 5 \text{ in} \times 2 \text{ ft/in} = 10 \text{ ft}$. 5. Actual length $= 8 \text{ in} \times 2 \text{ ft/in} = 16 \text{ ft}$. 6. Therefore, the real trampoline measures $10$ feet wide and $16$ feet long.