1. **Stating the problem:** We have a parallelogram JKLM with points J(3,3), K(4,3), L(4,1), and M(2,1). The figure is translated by the vector $$\begin{pmatrix} -6 \\ 2 \end{pmatrix}$$. We need to find the coordinates of points K' and M' after this translation. 2. **Formula for translation:** To translate a point $P(x,y)$ by a vector $$\begin{pmatrix} a \\ b \end{pmatrix}$$, the new point $P'(x',y')$ is given by: $$ x' = x + a \\ y' = y + b $$ 3. **Applying the translation to K(4,3):** $$ x' = 4 + (-6) = 4 - 6 = -2 \\ y' = 3 + 2 = 5 $$ So, $$K' = (-2, 5)$$. 4. **Applying the translation to M(2,1):** $$ x' = 2 + (-6) = 2 - 6 = -4 \\ y' = 1 + 2 = 3 $$ So, $$M' = (-4, 3)$$. **Final answers:** - Coordinates of $$K'$$ are $$(-2, 5)$$. - Coordinates of $$M'$$ are $$(-4, 3)$$.