1. The problem is to find the area of a trapezoid with bases $b_1 = 3$, $b_2 = 2$, and height $h = 2$. 2. The formula for the area of a trapezoid is: $$A = \frac{1}{2} \cdot (b_1 + b_2) \cdot h$$ This formula works because the area is the average length of the two parallel sides multiplied by the height. 3. Substitute the given values into the formula: $$A = \frac{1}{2} \cdot (3 + 2) \cdot 2$$ 4. Simplify inside the parentheses: $$3 + 2 = 5$$ 5. Now calculate the area: $$A = \frac{1}{2} \cdot 5 \cdot 2$$ 6. Multiply: $$\frac{1}{2} \cdot 2 = 1$$ 7. So the area is: $$A = 1 \cdot 5 = 5$$ Therefore, the area of the trapezoid is 5 square units.