1. **State the problem:** We need to find the area of a trapezoid with bases of lengths 14.9 ft and 8.3 ft, and a height of 9 ft. 2. **Formula for the area of a trapezoid:** $$A = \frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the lengths of the two bases, and $h$ is the height. 3. **Substitute the given values:** $$A = \frac{(14.9 + 8.3)}{2} \times 9$$ 4. **Simplify inside the parentheses:** $$14.9 + 8.3 = 23.2$$ 5. **Calculate the average of the bases:** $$\frac{23.2}{2} = \cancel{\frac{23.2}{2}} 11.6$$ 6. **Multiply by the height:** $$A = 11.6 \times 9 = 104.4$$ 7. **Final answer:** The area of the trapezoid is **104.4 square feet**.