1. **Problem statement:** We need to find the area of the logo on the work suit, which is shaped as shown with dimensions $a=28$ cm, $b=3$ cm, and $c=23$ cm. 2. **Understanding the shape:** The figure appears to be a trapezoid with parallel sides $a$ and $c$, and height $b$. 3. **Formula for the area of a trapezoid:** $$\text{Area} = \frac{(a+c)}{2} \times b$$ 4. **Substitute the given values:** $$\text{Area} = \frac{(28 + 23)}{2} \times 3$$ 5. **Calculate the sum inside the numerator:** $$\text{Area} = \frac{51}{2} \times 3$$ 6. **Simplify the fraction:** $$\text{Area} = \cancel{\frac{51}{2}} \times 3 = 25.5 \times 3$$ 7. **Multiply to find the area:** $$\text{Area} = 76.5$$ 8. **Final answer with units and rounding:** The area of the logo is **76.50 cm^2**.