1. **State the problem:** Find the area of a trapezoid with top base $19$ m, bottom base $30$ m, and height $6$ m. 2. **Formula for the area of a trapezoid:** $$A = \frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the lengths of the two bases, and $h$ is the height. 3. **Identify values:** - $b_1 = 19$ m (top base) - $b_2 = 30$ m (bottom base) - $h = 6$ m (height) 4. **Substitute values into the formula:** $$A = \frac{(19 + 30)}{2} \times 6$$ 5. **Simplify inside the parentheses:** $$A = \frac{49}{2} \times 6$$ 6. **Multiply:** $$A = 24.5 \times 6$$ 7. **Calculate the product:** $$A = 147$$ 8. **Final answer:** The area of the trapezoid is $147$ square meters.