1. **State the problem:** We need to find the area of a trapezoid with bases of lengths 18 inches and 7 inches, and a height of 20 inches.
2. **Formula for the area of a trapezoid:**
$$\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$$
3. **Identify the values:**
- Base 1 ($b_1$) = 18 inches
- Base 2 ($b_2$) = 7 inches
- Height ($h$) = 20 inches
4. **Substitute the values into the formula:**
$$\text{Area} = \frac{1}{2} \times (18 + 7) \times 20$$
5. **Simplify inside the parentheses:**
$$18 + 7 = 25$$
6. **Calculate the area:**
$$\text{Area} = \frac{1}{2} \times 25 \times 20 = \frac{1}{2} \times 500 = 250$$
7. **Final answer:** The area of the trapezoid is $250$ square inches.
Trapezoid Area 6D7B46
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