1. **Problem:** Find the area of trapezoid ABCD where AB and CD are parallel, AB = 10 units, height = 4 units, and CD = 5 + 5 = 10 units. 2. **Formula:** The area of a trapezoid is given by $$\text{Area} = \frac{(\text{Base}_1 + \text{Base}_2)}{2} \times \text{Height}$$ 3. **Apply values:** Here, Base_1 = AB = 10, Base_2 = CD = 10, Height = 4. 4. **Calculate:** $$\text{Area} = \frac{(10 + 10)}{2} \times 4 = \frac{20}{2} \times 4$$ 5. **Simplify:** $$= 10 \times 4 = 40$$ 6. **Check the figure:** The problem states AB and CD are parallel, but the figure shows AB = 10 and CD = 5 + 5 = 10, so the trapezoid is actually a rectangle with height 4 and bases 10. 7. **Final answer:** The area is 40 square units. **Note:** The options do not include 40, so re-examine the problem. 8. **Re-examination:** The figure shows AB = 10, height from A to DC is 4, and the segment DC is split into 5 and 5 units, so DC = 10. 9. **But the problem states AD = 5 units, and BC = 5 units, so the trapezoid is not a rectangle but a trapezoid with bases AB = 10 and DC = 10, height 4. Area is 40. 10. **Since 40 is not an option, check if the height is 4 or if the height is different. The height is given as 4 units. 11. **Conclusion:** The area is 40, but since 40 is not an option, the closest is 36 (A) or 52 (B). Possibly the height is 3.6 or 4.5, but given data is 4. 12. **Answer:** 40 (not listed), so select closest option 36. **Final:** Area = 40 square units (closest option A. 36).