1. **State the problem:** We need to find the area of a right trapezoid with bases 12.5 ft and 6 ft, and height 6 ft. 2. **Formula for the area of a trapezoid:** $$\text{Area} = \frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the lengths of the two bases, and $h$ is the height. 3. **Substitute the given values:** $$b_1 = 12.5, \quad b_2 = 6, \quad h = 6$$ 4. **Calculate the sum of the bases:** $$12.5 + 6 = 18.5$$ 5. **Calculate the average of the bases:** $$\frac{18.5}{2} = \cancel{\frac{18.5}{2}} 9.25$$ 6. **Calculate the area:** $$9.25 \times 6 = 55.5$$ 7. **Final answer:** The area of the trapezoid is $55.5$ square feet.