1. **State the problem:** We have trapezoid PQRS with vertices P(-7, -2), Q(-4, -1), R(-2, -5), and S(-8, -7). We need to find the coordinates of the reflected trapezoid P'Q'R'S' after reflecting over the x-axis. 2. **Reflection rule:** When reflecting a point $(x, y)$ over the x-axis, the x-coordinate remains the same, and the y-coordinate changes sign. The formula is: $$ (x, y) \to (x, -y) $$ 3. **Apply the reflection to each vertex:** - For $P(-7, -2)$: $$ P' = (-7, -(-2)) = (-7, 2) $$ - For $Q(-4, -1)$: $$ Q' = (-4, -(-1)) = (-4, 1) $$ - For $R(-2, -5)$: $$ R' = (-2, -(-5)) = (-2, 5) $$ - For $S(-8, -7)$: $$ S' = (-8, -(-7)) = (-8, 7) $$ 4. **Final answer:** $$ P'(-7, 2),\quad Q'(-4, 1),\quad R'(-2, 5),\quad S'(-8, 7) $$ These are the coordinates of the trapezoid after reflection over the x-axis.