1. **State the problem:** We have a right triangle with a hypotenuse of length 10 feet and one angle of 60°. 2. **Identify the sides:** In a right triangle with angles 30°, 60°, and 90°, the sides are in the ratio $1 : \sqrt{3} : 2$ where the hypotenuse is twice the shortest side. 3. **Find the missing sides:** Since the hypotenuse is 10 feet, the shortest side (opposite 30°) is $\frac{10}{2} = 5$ feet. 4. **Calculate the other leg:** The side opposite 60° is $5 \times \sqrt{3} = 5\sqrt{3}$ feet. 5. **Calculate the perimeter:** $$\text{Perimeter} = 10 + 5 + 5\sqrt{3} = 15 + 5\sqrt{3}$$ 6. **Calculate the area:** $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 5 \times 5\sqrt{3} = \frac{25\sqrt{3}}{2}$$ **Final answers:** - Perimeter = $15 + 5\sqrt{3}$ feet - Area = $\frac{25\sqrt{3}}{2}$ square feet