1. **State the problem:** We have a triangle with two angles measuring 64º each, and the third angle is labeled as $b$. We need to find the value of $b$. 2. **Recall the triangle angle sum rule:** The sum of the interior angles of any triangle is always 180º. 3. **Set up the equation:** Let the three angles be $64º$, $64º$, and $b$. Then, $$64 + 64 + b = 180$$ 4. **Solve for $b$:** $$b = 180 - 64 - 64$$ $$b = 180 - 128$$ $$b = 52$$ 5. **Conclusion:** The value of angle $b$ is 52º.