1. The problem asks for the sum of the interior angle measures of a triangle. 2. The formula for the sum of interior angles of any polygon with $n$ sides is: $$\text{Sum of interior angles} = (n-2) \times 180^\circ$$ 3. Since a triangle has $n=3$ sides, substitute into the formula: $$\text{Sum} = (3-2) \times 180^\circ$$ 4. Simplify the expression: $$\text{Sum} = 1 \times 180^\circ = 180^\circ$$ 5. Therefore, the sum of the interior angles of the triangle is $180^\circ$. This is a fundamental property of triangles: no matter the shape, the interior angles always add up to $180^\circ$.