1. **Problem statement:** Find the value of $x$ in the given triangles.
2. **Recall the triangle angle sum rule:** The sum of the interior angles in any triangle is always $180^\circ$.
### (a) Triangle angles: $(2x + 20)^\circ$, $70^\circ$, $80^\circ$
3. Write the equation for the sum of angles:
$$ (2x + 20) + 70 + 80 = 180 $$
4. Simplify the equation:
$$ 2x + 20 + 150 = 180 $$
$$ 2x + 170 = 180 $$
5. Solve for $x$:
$$ 2x = 180 - 170 $$
$$ 2x = 10 $$
$$ x = \frac{10}{2} = 5 $$
### (b) Triangle angles: $130^\circ$, $(6x - 7)^\circ$, $(x + 15)^\circ$
6. Write the equation for the sum of angles:
$$ 130 + (6x - 7) + (x + 15) = 180 $$
7. Simplify the equation:
$$ 130 + 6x - 7 + x + 15 = 180 $$
$$ 7x + 138 = 180 $$
8. Solve for $x$:
$$ 7x = 180 - 138 $$
$$ 7x = 42 $$
$$ x = \frac{42}{7} = 6 $$
**Final answers:**
- (a) $x = 5$
- (b) $x = 6$
Triangle Angles 8041B5
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