1. **Stating the problem:** We have a right triangle QRS with a right angle at Q.
2. **Given data:** Side QS = 2.25 cm and side QR = 3 cm.
3. **Formula for area of a right triangle:**
$$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$
4. Since Q is the right angle, sides QS and QR are perpendicular and can be considered as base and height.
5. Substitute the values:
$$\text{Area} = \frac{1}{2} \times 2.25 \times 3$$
6. Calculate the multiplication:
$$\text{Area} = \frac{1}{2} \times 6.75$$
7. Simplify the fraction:
$$\text{Area} = \cancel{\frac{1}{2}} \times 6.75 = 3.375$$
8. **Final answer:** The area of triangle QRS is **3.375 cm²**.
Triangle Area 748B96
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