1. **State the problem:** Find the area of the right triangle with vertices A(-5, 4), B(3, 4), and C(-5, 0). 2. **Formula for the area of a triangle:** $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ 3. **Identify base and height:** - The base is the horizontal segment AB since points A and B share the same y-coordinate 4. - The height is the vertical segment AC since points A and C share the same x-coordinate -5. 4. **Calculate the length of the base AB:** $$AB = |x_B - x_A| = |3 - (-5)| = |3 + 5| = 8$$ 5. **Calculate the length of the height AC:** $$AC = |y_A - y_C| = |4 - 0| = 4$$ 6. **Calculate the area:** $$\text{Area} = \frac{1}{2} \times 8 \times 4 = \frac{1}{2} \times 32 = 16$$ 7. **Final answer:** The area of the triangle is **16 square units**.