Question: Find the area of the triangle.
Right triangle in center-left with a vertical side labeled 24 m and a horizontal base labeled 16 m, right angle at the bottom-left corner.
a 216 m^2
b 141 m^2
c 192 m^2
d 268 m^2
1. **State the problem:** We need to find the area of a right triangle with legs of length $24$ m and $16$ m.
2. **Formula for the area of a triangle:**
$$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$
3. **Identify base and height:**
Since the triangle is right-angled, the two legs are perpendicular and can be considered as base and height.
Here, base $= 16$ m and height $= 24$ m.
4. **Calculate the area:**
$$\text{Area} = \frac{1}{2} \times 16 \times 24$$
5. **Simplify the multiplication:**
$$= \frac{1}{2} \times 384$$
6. **Simplify the fraction:**
$$= \cancel{\frac{1}{2}} \times 384 = 192$$
7. **Final answer:**
The area of the triangle is $192$ square meters.
**Answer: c) 192 m^2**