Subjects geometry

Triangle Area E4023C

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1. **Problem:** Find the area of a triangular plot of land with sides 240 ft, 300 ft, and 360 ft. 2. **Formula:** Use Heron's formula for the area of a triangle when all sides are known: $$s = \frac{a+b+c}{2}$$ $$\text{Area} = \sqrt{s(s-a)(s-b)(s-c)}$$ where $a=240$, $b=300$, and $c=360$. 3. **Calculate the semi-perimeter $s$:** $$s = \frac{240 + 300 + 360}{2} = \frac{900}{2} = 450$$ 4. **Calculate the area:** $$\text{Area} = \sqrt{450(450-240)(450-300)(450-360)}$$ $$= \sqrt{450 \times 210 \times 150 \times 90}$$ 5. **Simplify inside the square root:** $$= \sqrt{450 \times 210 \times 150 \times 90}$$ Calculate stepwise: $$450 \times 210 = 94500$$ $$150 \times 90 = 13500$$ $$94500 \times 13500 = 1,275,750,000$$ 6. **Find the square root:** $$\text{Area} = \sqrt{1,275,750,000} \approx 35717.4$$ 7. **Round to the nearest hundred square feet:** $$35700$$ 8. **Check the height given:** The problem states the height from vertex B to side AC is 135 ft. 9. **Alternative area calculation using base and height:** $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 360 \times 135 = 24300$$ 10. **Since the height is given, use this for area:** The area is $24300$ square feet. 11. **Compare with options:** None of the options match $24300$, so likely the problem expects the area using the height. 12. **Answer:** None of the options A-D match the calculated area using the height or Heron's formula. Possibly a typo or misinterpretation. Since the first question is about the triangular plot with sides 240, 300, 360 ft, and height 135 ft, the area is: $$\text{Area} = \frac{1}{2} \times 360 \times 135 = 24300$$ square feet. **Final answer:** $24300$ square feet (not among the given options).