1. **Problem:** Find the area of a triangular plot of land with sides 240 ft, 300 ft, and 360 ft.
2. **Formula:** Use Heron's formula for the area of a triangle when all sides are known:
$$s = \frac{a+b+c}{2}$$
$$\text{Area} = \sqrt{s(s-a)(s-b)(s-c)}$$
where $a=240$, $b=300$, and $c=360$.
3. **Calculate the semi-perimeter $s$:**
$$s = \frac{240 + 300 + 360}{2} = \frac{900}{2} = 450$$
4. **Calculate the area:**
$$\text{Area} = \sqrt{450(450-240)(450-300)(450-360)}$$
$$= \sqrt{450 \times 210 \times 150 \times 90}$$
5. **Simplify inside the square root:**
$$= \sqrt{450 \times 210 \times 150 \times 90}$$
Calculate stepwise:
$$450 \times 210 = 94500$$
$$150 \times 90 = 13500$$
$$94500 \times 13500 = 1,275,750,000$$
6. **Find the square root:**
$$\text{Area} = \sqrt{1,275,750,000} \approx 35717.4$$
7. **Round to the nearest hundred square feet:**
$$35700$$
8. **Check the height given:** The problem states the height from vertex B to side AC is 135 ft.
9. **Alternative area calculation using base and height:**
$$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 360 \times 135 = 24300$$
10. **Since the height is given, use this for area:**
The area is $24300$ square feet.
11. **Compare with options:** None of the options match $24300$, so likely the problem expects the area using the height.
12. **Answer:** None of the options A-D match the calculated area using the height or Heron's formula. Possibly a typo or misinterpretation.
Since the first question is about the triangular plot with sides 240, 300, 360 ft, and height 135 ft, the area is:
$$\text{Area} = \frac{1}{2} \times 360 \times 135 = 24300$$ square feet.
**Final answer:** $24300$ square feet (not among the given options).
Triangle Area E4023C
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