1. **Problem 1: Find the area of the triangle with base 11 in and height 8 in.** 2. The formula for the area of a triangle is: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ 3. Substitute the given values: $$\text{Area} = \frac{1}{2} \times 11 \times 8$$ 4. Calculate the multiplication: $$\text{Area} = \frac{1}{2} \times 88$$ 5. Simplify by dividing 88 by 2: $$\text{Area} = \cancel{\frac{1}{2}} \times \cancel{88} 44$$ 6. So, the area of the triangle is 44 in$^2$. --- 7. **Problem 2: Expressions for the area of the white figure formed by two squares, one inside the other.** 8. The white figure is the area of the larger square minus the area of the smaller square inside it. 9. The area of the larger square is $x^2$. 10. The area of the smaller square is $6^2 = 36$. 11. So, the area of the white figure is: $$x^2 - 6^2$$ 12. Check the options: - A. $(x - 6)^2$ is the area of a square with side $(x-6)$, not the white figure. - B. $2x + 2(x - 6)$ is a perimeter expression, not area. - C. $x^2 - 6^2$ is correct. - D. $x(x - 6) + 6(x - 6)$ simplifies to $(x + 6)(x - 6) = x^2 - 36$, which is also correct. - E. $6^2 - x^2$ is the negative of the white figure's area, so incorrect. 13. Therefore, the correct expressions are C and D. **Final answers:** - Area of triangle = 44 in$^2$ (Option C) - Expressions for white figure area: C and D