1. **State the problem:**
Classify triangle $\triangle TUV$ by its sides and angles.
2. **Recall classification rules:**
- By sides: Equilateral (all sides equal), Isosceles (two sides equal), Scalene (all sides different).
- By angles: Acute (all angles < 90°), Right (one angle = 90°), Obtuse (one angle > 90°).
3. **Apply to $\triangle TUV$:**
Since no side lengths or angle measures are given, we cannot classify $\triangle TUV$ specifically.
4. **Next problem:**
In $\triangle PQR$, given:
$$QR = PQ + 3$$
$$PR = PQ - 4$$
5. **Analyze side lengths:**
Let $PQ = x$.
Then $QR = x + 3$ and $PR = x - 4$.
6. **Order sides:**
Since $x - 4 < x < x + 3$, the sides in ascending order are:
$$PR < PQ < QR$$
7. **Recall angle-side relationship:**
In a triangle, the largest angle is opposite the longest side, and the smallest angle is opposite the shortest side.
8. **List angles from least to greatest:**
Opposite $PR$ is angle $Q$, opposite $PQ$ is angle $R$, opposite $QR$ is angle $P$.
So angles in ascending order:
$$\angle Q < \angle R < \angle P$$
**Final answer:**
The angles of $\triangle PQR$ from least to greatest are $\angle Q$, $\angle R$, $\angle P$.
Triangle Classification C2Db59
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