1. **Problem:** If $\triangle PQR \cong \triangle STV$, which sides and angles have equal measurements?
2. **Solution:**
- By definition of congruent triangles, corresponding sides and angles are equal.
- Corresponding sides: $PQ = ST$, $QR = TV$, $PR = SV$
- Corresponding angles: $\angle P = \angle S$, $\angle Q = \angle T$, $\angle R = \angle V$
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2. **Problem:** Identify the congruence theorem/postulate for each pair of triangles (a) through (d).
- Since the figures are not explicitly given here, typical congruence postulates are:
- SAS (Side-Angle-Side): Two sides and the included angle are equal.
- SSS (Side-Side-Side): All three sides are equal.
- AAS (Angle-Angle-Side): Two angles and a non-included side are equal.
- Based on the markings described:
- (a) SAS
- (b) SSS
- (c) AAS
- (d) SAS
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3. **Problem:** In an isosceles triangle, the angle at the base is $45^\circ$. Find the angle opposite to the base.
4. **Solution:**
- In an isosceles triangle, the angles opposite the equal sides are equal.
- Let the equal sides be the legs, and the base angles each $45^\circ$.
- Sum of angles in triangle: $180^\circ$
- Let the vertex angle be $x$.
- Equation: $x + 45 + 45 = 180$
- Simplify: $x + 90 = 180$
- Solve: $x = 180 - 90 = 90$
- So, the angle opposite the base is $90^\circ$.
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4. **Problem:** If the arms of two angles are parallel and both arms of each pair are in the same or opposite direction, prove these angles are congruent.
5. **Solution:**
- When two angles have their arms parallel and oriented similarly or oppositely, they are either corresponding angles or alternate interior angles.
- By the properties of parallel lines cut by a transversal, these angles are congruent.
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5. **Problem:** Find the measure of sides of triangle where $m\angle B = m\angle C$ and sides are given as:
- $A = (4x + 2)$ cm
- $B = (6x - 8)$ cm
- $C = (2x + 2)$ cm
6. **Solution:**
- Since $m\angle B = m\angle C$, sides opposite these angles are equal.
- Side opposite $\angle B$ is $AC$, side opposite $\angle C$ is $AB$.
- Given sides $B$ and $C$ correspond to these sides, so set $B = C$:
$$6x - 8 = 2x + 2$$
- Subtract $2x$ from both sides:
$$6x - \cancel{8} - 2x = 2x + 2 - 2x$$
$$4x - 8 = 2$$
- Add 8 to both sides:
$$4x = 10$$
- Divide both sides by 4:
$$x = \frac{10}{4} = 2.5$$
- Find side lengths:
$$A = 4(2.5) + 2 = 10 + 2 = 12$$
$$B = 6(2.5) - 8 = 15 - 8 = 7$$
$$C = 2(2.5) + 2 = 5 + 2 = 7$$
- So, sides are $A = 12$ cm, $B = 7$ cm, $C = 7$ cm.
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**Final answers:**
1. Corresponding sides and angles equal as $PQ=ST$, $QR=TV$, $PR=SV$ and $\angle P=\angle S$, $\angle Q=\angle T$, $\angle R=\angle V$.
2. (a) SAS, (b) SSS, (c) AAS, (d) SAS.
3. Angle opposite base is $90^\circ$.
4. Angles with parallel arms in same/opposite directions are congruent by parallel line angle properties.
5. Side lengths: $A=12$ cm, $B=7$ cm, $C=7$ cm.
Triangle Congruence 1E6B5F
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