1. **State the problem:** Given that $\overline{AB} \parallel \overline{DC}$, prove that $\triangle ABC \cong \triangle CDA$ using the flowchart proof. 2. **Given:** $\overline{AB} \parallel \overline{DC}$. 3. **Reason:** Given. 4. **Given:** $\angle BAC \cong \angle DCA$. 5. **Reason:** Parallel lines cut by a transversal form congruent alternate interior angles. 6. **Next step:** $\angle B \cong \angle D$. 7. **Reason:** Alternate interior angles are congruent because $\overline{AB} \parallel \overline{DC}$ and $\overline{AC}$ is a transversal. 8. **Next step:** $\overline{AB} \cong \overline{DC}$. 9. **Reason:** Given (or marked with two ticks indicating equal segments). 10. **Final step:** $\triangle ABC \cong \triangle CDA$. 11. **Reason:** By Angle-Side-Angle (ASA) congruence postulate, since two angles and the included side are congruent. This completes the flowchart proof showing $\triangle ABC \cong \triangle CDA$.