1. **State the problem:**
Given that \(\frac{DE}{GH} = \frac{DF}{GI} = \frac{EF}{HI}\), prove that \(\triangle DEF \cong \triangle GHI\).
2. **Understand the given:**
We have three equal ratios of corresponding sides of the two triangles:
$$\frac{DE}{GH} = \frac{DF}{GI} = \frac{EF}{HI}$$
This means the sides of \(\triangle DEF\) are proportional to the sides of \(\triangle GHI\).
3. **Recall the criteria for triangle congruence:**
To prove two triangles are congruent, we can use criteria such as SSS (Side-Side-Side), SAS (Side-Angle-Side), ASA, AAS, or RHS.
4. **Analyze the problem:**
Since the ratios of all three pairs of sides are equal, the triangles are similar by SSS similarity criterion. But the problem asks to prove congruence, not similarity.
5. **Check if the triangles are equilateral or isosceles:**
From the graph description, \(DE \cong EF\) and \(GH \cong HI\), meaning:
$$DE = EF \quad \text{and} \quad GH = HI$$
Since the sides are equal in pairs, and the ratios of corresponding sides are equal, the triangles are not just similar but also have equal corresponding sides.
6. **Use the given equal ratios and equal sides to prove congruence:**
Since \(DE = EF\) and \(GH = HI\), and \(\frac{DE}{GH} = \frac{EF}{HI}\), it follows that:
$$\frac{DE}{GH} = \frac{EF}{HI} = 1$$
Therefore:
$$DE = GH \quad \text{and} \quad EF = HI$$
7. **From the given \(\frac{DE}{GH} = \frac{DF}{GI} = \frac{EF}{HI}\), and now knowing \(DE = GH\) and \(EF = HI\), it follows that:**
$$DF = GI$$
8. **Conclusion:**
All three pairs of corresponding sides are equal:
$$DE = GH, \quad DF = GI, \quad EF = HI$$
Therefore, by the SSS congruence criterion, \(\triangle DEF \cong \triangle GHI\).
**Final answer:**
$$\triangle DEF \cong \triangle GHI$$
Triangle Congruence Bac9Db
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.