1. The problem asks to identify corresponding parts of two triangles based on given angles and side markings. 2. The triangles are labeled BDC and RSQ with angles: - Triangle BDC: $\angle B = 44^\circ$, $\angle D = 76^\circ$, $\angle C = 60^\circ$ - Triangle RSQ: $\angle R = 60^\circ$, $\angle S = 44^\circ$, $\angle Q = 76^\circ$ 3. Corresponding parts in congruent triangles match in order of vertices. Since angles correspond by size, we match: - $\angle B (44^\circ)$ with $\angle S (44^\circ)$ - $\angle D (76^\circ)$ with $\angle Q (76^\circ)$ - $\angle C (60^\circ)$ with $\angle R (60^\circ)$ 4. Therefore, the corresponding angles are: - $\angle B \cong \angle S$ - $\angle D \cong \angle Q$ - $\angle C \cong \angle R$ 5. For sides, markings indicate: - Side $BD$ in triangle BDC corresponds to side $SQ$ in triangle RSQ (both have two marks) - Side $BC$ in triangle BDC corresponds to side $RS$ in triangle RSQ (both have one mark) 6. The options given are: - $\angle D \cong \angle R$ (No, $\angle D$ corresponds to $\angle Q$) - $BD \cong QR$ (No, $BD$ corresponds to $SQ$) - $\angle C \cong \angle R$ (Yes) - $\angle B \cong \angle Q$ (No, $\angle B$ corresponds to $\angle S$) 7. Final correct correspondences from the options are only: - $\angle C \cong \angle R$ Hence, the only correct choice is $\angle C \cong \angle R$.