Subjects geometry

Triangle Dilation 605Fae

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1. **State the problem:** We need to find the image of triangle \(\triangle EFG\) after a dilation centered at the origin with scale factor \(\frac{1}{5}\). The original vertices are \(E(-10, 10)\), \(F(0, 10)\), and \(G(-4, -10)\). 2. **Formula for dilation:** The dilation of a point \((x, y)\) about the origin with scale factor \(k\) is given by: $$ (x', y') = (kx, ky) $$ 3. **Apply the dilation to each vertex:** - For \(E(-10, 10)\): $$ E' = \left(\frac{1}{5} \times -10, \frac{1}{5} \times 10\right) = (-2, 2) $$ - For \(F(0, 10)\): $$ F' = \left(\frac{1}{5} \times 0, \frac{1}{5} \times 10\right) = (0, 2) $$ - For \(G(-4, -10)\): $$ G' = \left(\frac{1}{5} \times -4, \frac{1}{5} \times -10\right) = \left(-\frac{4}{5}, -2\right) $$ 4. **Conclusion:** The image \(\triangle E'F'G'\) after dilation has vertices: $$ E'(-2, 2), \quad F'(0, 2), \quad G'\left(-\frac{4}{5}, -2\right) $$ This completes the dilation process.
E(-10,10)F(0,10)G(-4,-10)E'(-2,2)F'(0,2)G'(-0.8,-2)