1. **Problem statement:** We have a right triangle WZX with a right angle at X, angles $\theta = 73^\circ$ at Y and $\beta = 37^\circ$ at Z, and base $ZY = 349$ units. We need to find the height $h$ from W perpendicular to XY. 2. **Identify the triangle and angles:** Since $\theta + \beta = 73^\circ + 37^\circ = 110^\circ$, but the triangle is right angled at X, the angles at Y and Z must be complementary to 90° together. This suggests the triangle is right angled at X, with $\theta = 73^\circ$ at Y and $\beta = 37^\circ$ at Z. 3. **Use trigonometric relations:** The height $h$ is the length from W perpendicular to XY. Since $ZY = 349$ is the base opposite to angle $\theta = 73^\circ$, we can use sine or cosine to find $h$. 4. **Calculate height $h$:** In right triangle WZX, height $h$ corresponds to the side opposite angle $\beta = 37^\circ$ or adjacent to $\theta = 73^\circ$. Using sine of $\beta$: $$h = ZY \times \sin(\beta) = 349 \times \sin(37^\circ)$$ 5. **Evaluate $\sin(37^\circ)$:** $$\sin(37^\circ) \approx 0.6018$$ 6. **Calculate $h$:** $$h = 349 \times 0.6018 = 210.03$$ 7. **Final answer:** $$h \approx 210.03$$ units (rounded to nearest hundredth).